2007-11-11 04:47:42 · 8 answers · asked by candy 3 in Science & Mathematics ➔ Mathematics
factoring differences of power*
2007-11-11 04:52:37 · update #1
is this correct: (x^4-1)(x^3+x^2+x+1)?
2007-11-11 05:02:40 · update #2
oops i mean (x^4-2) (x^3+2x^2+4x+8)
2007-11-11 05:05:37 · update #3
x^4-16=(x^2+4)(x^2-4)=(x^2+4)(x+2)(x-2)
=(x+2i)(x-2i)(x+2)(x-2)
where i is the square root of -1
2007-11-11 04:53:05 · answer #1 · answered by lkjh 3 · 0⤊ 1⤋
(x ² - 4) (x ² + 4)
(x - 2) (x + 2) (x ² + 4)
2007-11-15 12:47:51 · answer #2 · answered by Como 7 · 1⤊ 0⤋
Don't listen to the first answer.
(x^2 + 4)(x^2 - 4) = (x^2 + 4)(x + 2)(x - 2)
2007-11-11 12:53:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
==> factor x^4-16
=(x^2+4)(x^2-4)
=(x^2+4)(x+2)(x-2)
2007-11-11 12:57:59 · answer #4 · answered by homercruzado 2 · 0⤊ 0⤋
x^4 - 16 = (x^2 - 4)(x^2 + 4) = (x - 2)(x + 2)(x^2 + 4)
The difference of two squares (twice).
2007-11-11 12:52:36 · answer #5 · answered by language is a virus 6 · 0⤊ 0⤋
Use the identity a^2 - b^2 = (a - b)(a +b)
In this case a^2 = x^4 and b^2 =16
x^4-16 = (x^2 -4) (x^2 +4)
2007-11-11 12:51:56 · answer #6 · answered by Any day 6 · 0⤊ 2⤋
x^4-16
(x^2+4)(x^2-4)
Check by FOIL ing
x^4-4x^2+4x^2-16
x^4-16
2007-11-11 13:15:48 · answer #7 · answered by Anonymous · 0⤊ 0⤋
a² - b² = (a+b)(a-b)
(x²)² - (4)² = (x² + 4) (x² - 4)
again (x²+4)((x)² - (2)²) =
(x²+4)(x+2)(x-2)
There's no point in simplifying it further
2007-11-11 12:58:13 · answer #8 · answered by A Little Sarcasm Helps 5 · 0⤊ 0⤋