HI *1000$CASHMONEY* I HAVE JUST THE CORRECT ANSWER THAT YOU ARE LOOKING FOR THAT CAN HELP YOU SOLVE YOUR PROBLEM.
(2x-1)/3 < -7
2x-1 < -21
2x < -20
x < -10
(8x-2)/2 > 7
8x-2 > 14
8x > 16
x > 2
2007-11-11 02:13:11
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answer #1
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answered by Anonymous
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oooooh! is that an absolute value thing? ok, you gotta treat them like 2 seperate problems for now. i suggest u cancel out the fractions to make it easier. So mult. the 1st one by 3 on both sides and the 2nd by 2. Then you just solve the equations and you should get: X is less thatn or equal to -10 OR X is greater than or equal to 2. I suggest you graph the answer on a number line just to make sense of it. then plug a number in and check it.
2007-11-11 10:15:02
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answer #2
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answered by taytay 2
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if its set out like this
(2x-1)/3(>=) 7 (>=) (8x-2)/2
2/3x-1/3 (less than or equal to) 7(greater than or equal to) 4x-2
if 2/3x-1/3=7
then 2/3x must equal 7.3333333
so x must equal 4.8 recurring (or less)
if 4x-2 =7
thn 4x must equal 9
so x must equa l2.25(or more)
so x must be greater than or equal to 2.25 but less than or equal to 4.8recurring
2.25(<=) x(<=) 4.8 recurring
hope this helps
2007-11-11 10:19:23
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answer #3
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answered by ljaybrad123 2
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As this is probably your howework, i'm making up my own inequalities, but the work is the same. Let's take (4x-2)/6 <3 and (4x-2)/6 >-3
For the first one. First get rid of the denominator. Since you divide by the denominator, to get rid of it multiply both sides by the denominator:
(4x-2)/6 *6 <3*6 so you get
4x-2 <18
Then you have to get he x term alone, so get rid of any addends since here you're subtracting, add to both sides:
4x-2+2 <18+2 so you get
4x < 20
Now get rid of any coefficients to do that, divide by the coefficient:
4x/4 <20/4 so you get
x<5
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for the second one same thing:
get rid of the denominator
(4x-2)/6 *6>-3*6
4x-2 > -18
Get rid of the addend
4x-2+2 > -18+2
4x > -16
get rid of the coefficient
4x/4>-16/4
x > -4
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******NOTE***** if your coefficient is negative, flip your sign!
2007-11-11 10:16:56
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answer #4
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answered by BrightSexyBaby23 3
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(2x-1)/3 < -7
2x-1 < -21
2x < -20
x < -10
(8x-2)/2 > 7
8x-2 > 14
8x > 16
x > 2
2007-11-11 10:11:06
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answer #5
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answered by norman 7
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(2x-1)/3 < -7
2x-1 < -21
2x < -20
x < -10
(8x-2)/2 > 7
8x-2 > 14
8x > 16
x > 2
well i think you should go to homework.com i am avril want to be my friend?my e mail is miranda13_cosgrove@yahoo.co.uk
2007-11-11 10:12:55
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answer #6
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answered by avril 1
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Confused?
2007-11-11 10:08:53
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answer #7
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answered by Anonymous
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xis lessthan/equal to 10
xis greater than/equal to 2
2007-11-11 10:10:53
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answer #8
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answered by sexy joker 6
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Super easy question, it won't help if i told you the answer but i will suggest www.homework.com it will give u a good answer
2007-11-11 10:10:49
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answer #9
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answered by Anonymous
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the best website for this is www.purplemath.com which explains it very nicely under inequalities
2007-11-11 10:17:14
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answer #10
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answered by a c 7
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