Al(NO3)3 + Ba(OH)2 ----> Al(OH)2 + Ba(NO3)3
2007-11-10 05:41:52 · 5 answers · asked by Emerson 5 in Science & Mathematics ➔ Chemistry
For those of you who think its balanced, it is not. Count the charges on the products and you will see. Al has a +3
2007-11-11 01:54:52 · update #1
Aluminum occurs as Al3+, and Barium as Ba2+.
So you will be making Al(OH)3 and Ba(NO3)2; the formulas you have got written on the right-hand side must be wrong.
Balancing means that atoms are neither created or destroyed. In this case, the number of Al etc. and of OH on the left-hand side has got to the end up the same as the number on the right-hand side.
You want an even number of nitrates. So try 2 Al(NO3)3.
If you have2 Al, and each Al ends up with 3 NO3, how many NO3 do you need? How many Ba(NO3)2 will you need to supply that many NO3?
Once you have answered these questions, you will be able to balance the equation
2 Al(NO3)3 + etc.
2007-11-10 06:13:22 · answer #1 · answered by Facts Matter 7 · 0⤊ 0⤋
first, you identify the elements on each side of the equation. then, figure out how many atoms of each elements you have on the left and right sides of the equation. third, check if the equation is already balanced. use coefficients to balance the equation. start with the smallest whole number on the elements. balance the rest of the equation by adjusting the substance with the lower coefficient. finally, adjust the coefficients to complete the balanced equation.
the equation is balanced.
Al(NO3)3 + Ba(OH)2 = Al(OH)2 + Ba(NO3)3
an example of it would be:
AgNO3 + H2S = Ag2S + HNO3
Balanced equation:
2 AgNO3 + H2S = Ag2S + 2 HNO3
2007-11-10 06:07:47 · answer #2 · answered by darlene m 1 · 0⤊ 0⤋
N2 + 3H2 => 2NH3 you purely ought to have a similar form on each and each and every aspect. So at the same time as reckoning on the unique, you word that the left aspect has 2 H notwithstanding the right aspect as 3 H the bottom elementary denominator, with a view to talk, is 6, so that you get on the left aspect 3H2 (6 hydrogens) and on the right aspect you get 2NH3 (6 hydrogens). The nitrogens come out tremendous with 2 on each and each and every aspect.
2016-10-23 23:49:40 · answer #3 · answered by ? 4 · 0⤊ 0⤋
It is balanced. You can determine this by counting the number of each type of atom on each side of the equation to ascertain that they are equal.
2007-11-10 06:08:06 · answer #4 · answered by Tim C 7 · 0⤊ 0⤋
The equation is already balanced
2007-11-10 05:53:25 · answer #5 · answered by burgler09 5 · 1⤊ 0⤋