2007-11-09 20:53:02 · 13 answers · asked by Anonymous in Cars & Transportation ➔ Car Makes ➔ Dodge
top speed of my bike is 144 MPH
2007-11-09 21:06:42 · update #1
If he catches me and gets me for a DUI, I can lose my job cause my job requires a clean drivers licence
2007-11-09 21:08:44 · update #2
Motorola can out run that bike of yours in a 1963 bug (32hp).
In any event to out run the police you have to have two things, a darn good head start. a good lay of the roads, and 45 seconds. anything past that and Mr two way radio is going to get you
I have been busted for that stupid crap 4 times and have pulled it off 6 times. the ones that worked was Kawasaki 250cc Mach I, Yamaha V Max, 1976 F100 (300 six) 1969 Hurst Olds 442. The stuff that did not work, 1987 Kawasaki 750 Ltd, 1972 Montego (428cid) 1991 Corvett.
The total fun, loosing cars and fines and total of 90 days in jail was well over $50,000
So go knock yourself out, be dumb, and be ready to pay cash, cars, your life, and maybe someonelses
By the way in many states it it cald feloney aluding. and nothing will put a nox nix on jobs etc than a felony. That way when you do smartenup u can cry about it the rest of your life
2007-11-10 01:04:50 · answer #1 · answered by Anonymous · 1⤊ 0⤋
I don't know about a Charger cop car but the Dodge Charger SRT-8 NASCAR special edition is registered for 170mph. You won't out run him in a long distance, but you should probably blow his doors on take off. As far as your bike handling better than this car I seriously doubt it. This thing is on a rail. The only thing that even comes close to it that I have personally driven is the Z-3 roadster.
All things considered, if you go out and drink call a cab. You'll still have a job, be on the free side of the iron bars, and above ground when you sober up.
2007-11-09 23:53:22 · answer #2 · answered by Anonymous · 2⤊ 0⤋
More than likely cuz the Charger only has top speed of about 150-160 mph, plus the bike is more maneuverable, he'll have to slow down more in corners. The best bet though- don't run from the cops.
2007-11-09 21:05:29 · answer #3 · answered by Foxstanger 1 · 2⤊ 1⤋
You know a normal charger tops out at 150-160 but since its a cop car it'll probably push about 210 and a new charger will beat out a porche with 0-60 in like 3.8 seconds so if I was you I wouldn't mess with that!!!!
2007-11-10 07:15:25 · answer #4 · answered by Anonymous · 2⤊ 0⤋
Well you are entering into a Felony when you run from the police, so in addition to losing your job, you might lose your freedom. Seriously in the worse case you could have an accident and hurt someone and boy will you have a mountain of legal troubles you don't even want to think about.
Try this, don't drink and drive! Especially on a bike!
2007-11-09 21:39:54 · answer #5 · answered by Ken L 3 · 6⤊ 0⤋
The charger will catch you, it is "chipped out" at 150 mph and contrary to popular belief, a car is more maneuverable than a bike, especially at high speed. With 4 tires on the ground rather than two, cars stop faster and turn quicker. A bike's size and acceleration are it's only advantages.
2007-11-09 21:18:34 · answer #6 · answered by Cecil n 7 · 4⤊ 1⤋
Our police drive mainly old Ford Crown Victorias. They also have a couple of old Chevy Silverados. There are also several Chevy Tahoes. Neighboring cities have the new Dodge Chargers, but yet to see one in my city.
2016-05-29 01:27:29 · answer #7 · answered by jennette 3 · 0⤊ 0⤋
The base model (V6) police Charger will run 132, the V8 will do 148.
2007-11-10 08:46:34 · answer #8 · answered by eferrell01 7 · 2⤊ 0⤋
u might out run that car but what about every other police vehicle including a helicopter good luck dont bother trying u will end up in jail they only have to get your rego plates and your done dont try it its not worth killing yourself or someone else over anything so stupid
2007-11-09 22:52:32 · answer #9 · answered by mr & mrs b 3 · 3⤊ 0⤋
I agree with the others plus, the Dodge has a Radio and I doubt if anything can outrun that!!
2007-11-09 21:25:22 · answer #10 · answered by Chewbydoo 5 · 3⤊ 0⤋