They will hit the ground at the same time. This is due to the fact that gravity will acting on both bullets is the same -9.81m/s^2.
2007-11-07 15:55:20
·
answer #1
·
answered by sportsmess 3
·
9⤊
0⤋
Haven't we answered this question about 4 or 5 times in the last couple of months? Yahoo really should have a list of frequently asked questions so we don't keep getting the same old questions over and over.
Sarge
Answer They would both hit the ground at the same time except I have no idea what a hop up is?
2007-11-11 12:22:56
·
answer #2
·
answered by sargeArmy 4
·
0⤊
0⤋
In theory, both will hit the ground at the same time. Both bullets will be acted upon equally by gravity. The only difference is one bullet will hit the ground just below the muzzle of your gun and the other will hit the ground at some distance but both will hit the ground at the same time.
2007-11-08 05:04:55
·
answer #3
·
answered by Anonymous
·
1⤊
0⤋
If I understand your question right, that you would fire a bullet across, say, an open field, and at the same time drop a bullet straight down, they would both land at the same time, gravity has an equal acceleration on any mass, the only reason something may not fall as fast as something else would be air resistance. For example a piano and a feather would both hit the ground at the same time if they were dropped in a sealed environment without air.
2007-11-07 15:57:22
·
answer #4
·
answered by Chuck 2
·
6⤊
0⤋
Assuming that (1) the ground was level, and (2) you shot the gun completely level to the ground, the bullets would hit the ground at the same time. The pull of gravity is uniform on all things.
2007-11-07 16:13:09
·
answer #5
·
answered by Corvo 5
·
5⤊
0⤋
You say hop up, so I'm going to assume you mean a smoothbore musket, paintball, or airsoft gun. While it's true that a rifle round rotates and generates an infantecimal amount of lift, a round ball with no rotation or backspin will accelerate at exactly the same rate as ball dropped, but lighter plastic or paintballs, because of the lateral air resistance, may have a slightly lower drop.
2007-11-08 04:08:53
·
answer #6
·
answered by fishtrembleatmyname 5
·
0⤊
1⤋
As the bullet fired from the gun moves away from the shooter it also moves away from the earth because as we all know, the earth is not flat.Therefore that bullet has farther to fall and will strike second.
2007-11-09 15:37:10
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
if you could fire a bullet at a speed of approximately 1,500,000 feet per second with no air resistance(in a vacuum) it could go around the earth & hit the back of the gun it was fired from.
but since burning gun powder expands at a rate of less than 6000 fps & cant make a bullet go that fast they will both hit at the same time. according to my timex watch.
2007-11-08 00:20:23
·
answer #8
·
answered by Who Dat ? 7
·
1⤊
2⤋
Sportsmess and Chuck are absolutely correct, as they would in fact hit the ground at the same time.Simple Physics....I am thinking you meant to say "flat trajectory" and not "hop-up" as you wrote it.....and you meant to say "hits the ground first" in place of "which grounds 1st "....
Thumbs Up Guys!
2007-11-07 16:06:43
·
answer #9
·
answered by JD 7
·
2⤊
5⤋
You won't accept it, but you lot are wrong. Not by much, but in absolute terms you are.
When you fire a rifled round, and I'm assuming a single shot is going to be rifled, the round takes a slight point upwards attitude after falling a very short distance. Once it has done that the round has a tiny amount of aerodynamic lift, so it falls slower.
Basic classical physics doesn't provide all the answers when you are interested in a precise answer.
2007-11-07 19:32:53
·
answer #10
·
answered by Chris H 6
·
1⤊
7⤋