12 * 200 = 2400 Watt-hours, so theoretically it could last 2.4 hours.
In practice when you discharge a lead-acid battery at a high rate (in this case Capacity / 2.4 -- which is a high rate), you don't get all that energy. In your case you will probably get about 1 hour of useful life.
If you have an inverter that operates at lower and lower battery voltage, then you could get an hour-and-a-half or more.
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2007-11-07 05:43:39
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answer #1
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answered by tlbs101 7
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2.4 hours is what you get from dividing the power usage into the battery's capacity. But amp-hour ratings are done at a 20-hour constant discharge. At higher currents, battery capacity is less.
Two other considerations are 1) if the battery is not designed for deep discharge service, it will be damaged by this kind of use, and 2) voltage drops as the battery discharges, and it may be too low for your application while the battery still technically has charge left .
I usually figure on using half of a battery's rated capacity. If it's important to know exactly how long yours will hold up, you'll need actual test data. Keep in mind that service temperature may have an effect, too.
2007-11-07 06:42:00
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answer #2
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answered by injanier 7
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at 1000Watts thats around 100 Amps
(allowing for losses and discharge rate)
so no more than 2 hours
But some technologies are not meant to be completely discharged. The lead -acid (car battery) should not go below 25%
So a realistic answer is nearer 1 hour
2007-11-07 07:51:36
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answer #3
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answered by Anonymous
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First, for a 98W amp and a 240W reveal, you will choose a minimum of 338 watts non-end, and the startup load would be 2 consistent with possibility thrice that quantity; a three hundred-watt inverter basically won't do it. 2d, in the experience that your battery is a cranking battery, you do not choose to discharge it under ninety%, 80% tops. you like a "deepcycle" battery. Your calculations for the amp artwork out notably solid. yet another attitude: to make certain that the 12 volt battery to make ninety 8 watts, it is going to could desire to placed out 8 amps plus 5% for the inverter overhead, call it 9 amps (ninety 8 x one million.05 / 12), which the inverter will convert into .41A at 240V. 55ah at 9 amps is 6.one million hours. The liquid crystal reveal reveal will drain the battery very immediately.
2017-01-05 02:38:50
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answer #4
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answered by Anonymous
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12V X 200Ah = 2400Wh
2400Wh/1000W = 2.4h
That assumes that the battery is designed to discharge at that rate without overheating and that the Ah rating is valid for that discharge rate.
2007-11-07 05:55:34
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answer #5
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answered by EE68PE 6
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Given an efficiency of about 80%:
hours = (200Ah * 12V * 0.8) /1000W
hours = 1920AhV/1000W
hours = 1.920
2007-11-07 05:43:09
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answer #6
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answered by Anonymous
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200ah Battery
2016-10-01 07:21:19
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answer #7
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answered by quinillo 4
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25 minutes. 1000/(12*200) converted from hours into minutes.
2007-11-07 05:22:43
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answer #8
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answered by alfred a 2
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donno
2015-05-08 01:29:41
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answer #9
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answered by Sunny 1
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