how much voltage of continuous dc current is needed to push 100 kg of weight at 30 kmph 2 hours on even sur

Answer 1

The amount of power needed to keep the weight moving depends on the resisting forces - friction and air resistance. On a frictionless surface it needs no push at all to keep moving. And your answer will be in power units (watts), not volts, unless you have a fixed value of current.

Answer 2

Power in watts will do all the work you need but you have two unknowns. Voltage and current which are elements of the formula power = voltage x current.

You then have unlimited answers.

example answer: 5watts

5volts x 1 ampere = 5 watts
1volts x 5 ampere = 5 watts
2volts x 2.5ampere = 5 watts

Answer 3

Well electrical power is given by

P = IV where I is the current and V is the voltage and P is the power

P in mechanics = Fd/t = Fv = mgv where m is the mass, g is gravity, and v is the velocity. Translating to all standard units we get

IV = (100 kg)(9.81 m/s^2)(30000 m/s)

So V (in Volts) is given by

V = 29430000 J / (x)

Where x is the current in Amperes