farad to ampere?

Question

if the capacitance of a capacitor is x farad, then how do i count the total current release if the capacitor fully discharge in an instant? Can someone tell me the formula or any method on how to count it?

Answer 1

i = - CdV/dt = V/R
dV/V = - dt/RC
ln(V/V0) = (t - 0)/RC
V = V0e^-t/RC
i = V/R = (V0/R)e^-t/RC
so the initial current is inversely proportional to the resistance of the discharging circuit and directly proportional to the initial voltage across the capacitor, and decays with a time constant of RC.

Answer 2

Farad is the unit of capacitance when one coulomb of charge given to its plates raises its potential difference by one volt.

Q(coulomb) = C(farad) x E(volt)

I(ampere) = P(Volt-Ampere) x C(farad) / Q(coulomb)

Answer 3

1 Ampere is the current when 1 coulomb passes a given point in 1 second.

I=q/s

Answer 4

Your dealing in apples and oranges here. A farad is a measure of capaitance. Ampear is measure of curent flow. Got a lot of science to cover before you can get there from here. Like overcoming the time/space continium as espoused in the movie "Back to the Future"

Take a Pepsi and call me in the morning.