Im in a confusion. Imagine if two objects were squashed when dropped and both returned to their original states.
However, one of them deformed less in comparison to the other before it returned to its original state.
Does this mean that the object that deformed less is more elastic, does this also mean that it will lose less energy to the surroundings?
2007-11-05 09:53:25 · 5 answers · asked by saman-a-man 1 in Science & Mathematics ➔ Engineering
less elastic and no it will recieve more energy
2007-11-05 09:57:52 · answer #1 · answered by tazmatic1 4 · 1⤊ 0⤋
Your question is theoretically wrong. If the two objects return to their previous states, it means there was no energy transformation and thus deformation should not occur in either object.
Perfect Elastic object returns to original state.
Plastic object will get deformed and thus unable to return to original state.
2007-11-05 22:52:25 · answer #2 · answered by Lonewolf 2 · 0⤊ 0⤋
the more elastic a material the more energy it can absorb without being permantly (plastically) deformed.
If it deforms less it has a higher youngs moduls because it is more brittle.
2007-11-05 17:57:55 · answer #3 · answered by My pic looks good 2 · 0⤊ 0⤋
The shape and weight would have something to do with it and of course the material it was made of e.g.
Glass would break Plastic would bounce and not break.
2007-11-05 17:57:24 · answer #4 · answered by Sally Anne 7 · 0⤊ 0⤋
not necessarily.
2007-11-05 17:56:13 · answer #5 · answered by thegermanwall 2 · 0⤊ 0⤋