2007-10-30 18:59:33 · 7 answers · asked by johnny b 2 in Science & Mathematics ➔ Mathematics
think of tan 3x as tan u, with u=3x.
use the chain rule. the derivative of tan x is sec^2 x. but then it is tan u, so derivative is = sec^2 u.
the final answer would be: 3sec^2 3x.
2007-10-30 19:04:53 · answer #1 · answered by unean_amigo 3 · 0⤊ 0⤋
Derivative Of Tan 3x
2016-11-16 13:53:30 · answer #2 · answered by ? 4 · 0⤊ 0⤋
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RE:
how do you find the derivative of tan 3x?
2015-08-15 06:13:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋
d tan(u) = sec^2 u du. This last piece, du, is the chain rule.
NOW, d tan(3x) = sec^2(3x) d (3x)
= sec^2(3x)* 3 or
= 3 sec^2(3)
2007-10-30 19:03:34 · answer #4 · answered by Anonymous · 1⤊ 0⤋
First apply the quotient rule,
d(u / v) = (v du - u dv) / v^2;
Next, evaluate the embedded derivatives.
Now substitute and simplify.
If, like many normal people, you don't remember such things as
d(tan x) = sec^2 x dx,
you can apply the quotient rule to
tan x = sin x / cos x.
2007-10-30 19:09:50 · answer #5 · answered by Anonymous · 1⤊ 0⤋
tan 3x
Chain rule since it is a function:
Sec^2(3x)(3x)'
3sec^2(3x)
2007-10-30 19:09:27 · answer #6 · answered by nebulus9 2 · 0⤊ 0⤋
y = tan (3x)
Let u = 3x
du/dx = 3
y = tan u
dy/du = sec ² u
(dy/dx) = (dy/du) (du/dx)
dy/dx = (3) sec ² u
dy/dx = 3 sec ² 3x
2007-10-31 03:22:56 · answer #7 · answered by Como 7 · 0⤊ 0⤋
use chain rule
2007-10-30 19:31:09 · answer #8 · answered by mohammad s 1 · 0⤊ 0⤋