x^2 + 4x + 4 = 13
x^2 + 4x - 9 = 0
x = -4 +/- (1/2 ^(16 + 36)) / 2
= -4 +/ - (1/2 ^(52) ) / 2
x = 1.606 or x = -5.606
2007-10-30 18:19:55
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answer #1
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answered by Adobe 3
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x + 2 = ± √13
x = - 2 ± √13
2007-10-31 03:10:23
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answer #2
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answered by Como 7
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(x + 2)^2 = 13
x + 2 =√13
x + 2 - 2 = [(13)^1/2] -2
x + 0 = 13^1/2 - 2
x = 1.60555
2007-11-01 16:17:35
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answer #3
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answered by Rayan Ghazi Ahmed 4
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Three lines:
(x+2)^2 = 13
x+2 = +/- sqrt(13)
x = +/- sqrt(13) - 2
2007-10-30 18:20:09
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answer #4
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answered by RareOne 2
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If (x+2)^2 = 13
(x+2) = +/- SQRT(13)
Then x = +/- SQRT(13) - 2
Where SQRT is the square root, and +/- is plus/minus or positive/negative.
This means you have two different answers for x, approximately 1.6 and -5.6.
2007-10-30 18:25:31
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answer #5
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answered by Anonymous
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ax²+bx+c=0
!st)Expand every term in the parenthesis.
2nd)Rearrange the whole equation into a general form.
3rd)Carry out normal computation.
4th)Solve the equation by (i)factorisation(ii)completing the square(iii)quadratic formula
Method (iii) is employed as (i) and (ii) can't solve it.
The formula is x=[-b±√(b²-4ac)]/2a where x is the answer
4th)Substitute all the term into the equation accordingly.
(x+2)²=13
x²+4x+4=13
x²+4x-9=0
Let x=[-b±√(b²-4ac)]/2a
x={-4±√[4²-4(1)(-9)]}/2(1)
=(-4±√52)/2
=1.6056,-5.6056(5 significant figures)
2007-10-30 19:03:34
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answer #6
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answered by Anonymous
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(x+2)^2=13
(x+2) = +/- sqrt(13)
x = -2 +/- sqrt(13)
x = -2 + sqrt(13)
x = -2 - sqrt(13)
2007-10-30 18:22:41
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answer #7
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answered by Shh! Be vewy, vewy quiet 6
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x^2 + 4x + 4 = 13
x^2 +4x -9 = 0
use the quadratic formula
x = (-4 +- sqrt(16+4(9))/2
x=(-4 +- 7.2111)/2
x = 1.606 and x = -5.606
2007-10-30 18:16:21
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answer #8
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answered by MARS 3
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x2+2 2=13
x2+4=13
x2=13-4
x= 2 \ 9
x=3
2007-10-30 18:11:46
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answer #9
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answered by yasmin g 2
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x = 3/5
nvm thats wrong
srry
the person on top of mine is probably right
2007-10-30 18:20:39
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answer #10
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answered by vennysweetgirl21 3
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