john saw 3 witches land in a field where they found a pile of pumpkins and a ghost. they agree to sleep over night in the field and divide up the pile of pumpkins up in the morning. during the night one witch wakes up and gives one pumpkinto the ghost taking exaclty 1/3 of the rest of pumpkins and falls back asllep. then the second witch wakes up and does the samething later the third witch wakes up and does the same. in the morning there are fewer than 10 pumkins left. they each take 1/3 how many pumpkins were there in the original pile?
2007-10-30 16:19:17 · 5 answers · asked by batgirl 2 in Science & Mathematics ➔ Mathematics
X=1/3(x-1)+1/3(2/3(x-1)-1)+
1/3(2/3(2/3(x-1)-1)-1)+9.
or
X=1/3(x-1)+1/3(2/3(x-1)-1)+
1/3(2/3(2/3(x-1)-1)-1)+6.
or
X=1/3(x-1)+1/3(2/3(x-1)-1)+
1/3(2/3(2/3(x-1)-1)-1)+3.
Solve for X
2007-10-30 16:32:18 · answer #1 · answered by Q L 1 · 0⤊ 0⤋
7
2007-10-31 12:42:33 · answer #2 · answered by Lulu L 1 · 0⤊ 0⤋
There is no answer to this ?. It is a "trick" not a "treat" ?. All 3 witches took 1/3 of a whole wich leaves nothing for them to divide in the morning. The ghost kinda got screwed though he only got 3.
2007-10-30 23:29:20 · answer #3 · answered by nutnut's daddy 3 · 0⤊ 0⤋
(2/3)((2/3)((2/3)(n - 1) - 1) - 1) < 10
(2/3)((2/3)(n - 1) - 1) - 1 < 15
(2/3)((2/3)(n - 1) - 1) < 16
(2/3)(n - 1) - 1 < 24
(2/3)(n - 1) < 25
n - 1 < 37.5
n < 36.5
n = 25
check:
2(25 - 1)/3 = 16
2(16 - 1)/3 = 10
2(10 - 1)/3 = 6
2007-10-30 23:51:28 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
20?
2007-10-30 23:23:45 · answer #5 · answered by Anonymous · 0⤊ 0⤋