Could someone help me on physics problem dealing with magnitude?

Question

A 75kg bobsled is pushed along a horizontal surface by 2 athletes. after the bobsled is pushed a distance of 4.5 m starting from rest, its speed is 6.0 m/s. find the magnitude of the net force on the bobsled. is the answer 300N?

*i think this problem has something to do with the work kinetic energy thm.

Answer 1

It's 1000 N actually.

Answer 2

try this route for a solution
you know that at time t=0 the bobsled is at position x0=0, with speed v0=0. we also know that at some time T the bobsled is at x=4.5 m and v=6 m/s.

so if you use the equations of motion, x=x0+v0*t+a*t^2/2 and v=v0+a*t we know after plugging everything in

4.5 m = 0+v0*T+aT^2/2=aT^2/2
6m/s=0+aT

so we have two variables and two equations. dividing the first by the second
4.5/6 s= aT^2/(2aT)=T/2 or T=9/6 s =1.5 sec

no return to the equation for speed, v=6 m/s = a T = 1.5 a s

so a=4 m/s^2.

Finally force = ma=75 kg * 4 m/s^2=300 kg*m/s^2=300 N

Answer 3

The iceboat is being speeded up for 3.0s so the acceleration isn't 0. because of the fact the iceboat began from relax and the acceleration is persevering with, you need to use the formulation x = 0.5at^2 for the displacement, which seems to be approximately 27. 27 = 0.5a*9 --> a = 6m/s^2 due east For the subsequent question, basically calculate v = at because of the fact that acceleration is persevering with. v = 6m/s^2 * 3s --> v = 18m/s due east v is a vector. Assuming that the boat grow to be not shifting interior the north-south path whilst the wind began blowing, the magnitiude is basically 18m/s Now basically use the 1st formulation and make larger it to 6s from 3s x = 0.5at^2 --> x = 0.5*6*6^2 --> x = 108m after 6s however the boat moved 27m after the 1st 3s so it moved 108 - 27 = 81m interior the 2d 3 2nd iinterval.

Answer 4

300 N is correct.

F=ma m=75 kg

must find a

v=at and d=1/2 a t^2 = 1/2 vt

solve for t

t=v/a and t = 2d/v so v/a=2d/v

rearrange to solve for a a= v2/2d = 36/9=4 M/s^2

F = 75 Kg * 4 M/s^2 = 300 N

Answer 5

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