1. √4x+1+3=0
2. √2y+7+4=y
2007-10-30 13:35:24 · 3 answers · asked by tricey7578 2 in Science & Mathematics ➔ Mathematics
plug in your answer for x in #1 and your answer for y in #2 once you think you have the answer
2007-10-30 13:44:29 · answer #1 · answered by Laura W 2 · 0⤊ 0⤋
Hello,
1. subtract 3 from both sides and we have sqrt(4x +1) = -3 no solution!
2. subtract 4 from both sides and we have sqrt(2y +7) = y -4 now square both sides giving us 2y + 7 = y^2 -8y + 16 so
0 = y^2 -10y + 9. We have (y-9)(y-1) = 0 so y = 9 or y = 1
Check sqrt(2*9+7) + 4 =? 9 sqrt(25) + 4 =? 9 yes.
sqrt(2*1+7) + 4 = ? 1 no
so the Solution is y = 9
Hope This Helps!.
2007-10-30 20:51:27 · answer #2 · answered by CipherMan 5 · 0⤊ 0⤋
Get the instructors manual...
2007-10-30 20:42:43 · answer #3 · answered by rammuniz@sbcglobal.net 2 · 0⤊ 0⤋