s e e
+ y o u
= s o o n
2007-10-30 13:29:08 · 7 answers · asked by raj 1 in Science & Mathematics ➔ Mathematics
. SEE
+YOU
--------
SOON
Obviously S must be 1 and Y must be 8 or 9. We have E + O yielding O, so either E is 0 and there was no carry in, or there was a carry in and E = 9. But if E = 0 then the last digit of the result would be U. So E = 9 and Y = 8. Since we have 199 + something in the range 802-876, the result must start with the digits 10, so O must be 0. So we have 199 + 80U = 100N. There are several possible solutions; all we can say is that N = U-1 and they can't use any of the previous digits, so it could be any of these:
. 199
+803
--------
1002
. 199
+804
--------
1003
. 199
+805
--------
1004
. 199
+806
--------
1005
. 199
+807
--------
1006
2007-10-30 13:40:24 · answer #1 · answered by Scarlet Manuka 7 · 2⤊ 0⤋
Possible Solutions:
s=1, y=8, e=9, o=0,
u=7, n=6
or
u=6, n=5
or
u=5,n=4
or
y=4,n=3
or
u=3,n=2
2007-10-30 13:35:48 · answer #2 · answered by Anonymous · 2⤊ 0⤋
There are more than 1 answer that will work
here is one possible solution
o = 0 , s = 1 , n = 6 , u = 7 , y = 8 , e = 9
199 + 807 = 1006
2007-10-30 13:41:12 · answer #3 · answered by Martin B 1 · 0⤊ 0⤋
199 + 803 = 1002 works.
There are many other possibilities.
2007-10-30 13:44:47 · answer #4 · answered by Dr D 7 · 0⤊ 0⤋
Your on your own bro....
2007-10-30 13:33:06 · answer #5 · answered by Jim S 1 · 0⤊ 0⤋
19,5,5+25,15,21=19,15,15,14
2007-10-30 13:35:34 · answer #6 · answered by La Princesa 3 · 0⤊ 0⤋
**** question
2007-10-30 13:32:24 · answer #7 · answered by Deano 2 · 0⤊ 0⤋