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I don't understand this stuff at all. Please show some work.


Tarzan, whose mass is 85.0 kg, swings from a 3.50 m vine that is horizontal when he starts. At the bottom of his arc, he picks up 60.0 Jane in a perfectly inelastic collision. What is the height of the highest tree limb they can reach on their upward swing?

2007-10-30 12:37:08 · 2 answers · asked by Brittany F 2 in Science & Mathematics Physics

2 answers

This is solved through a combination of energy conservation and conservation of momentum.

Step 1: Use conservation of energy to equate Tarzan's gravitational potential energy at the top of his downswing to his kinetic energy at the bottom of his downswing (immediately before he grabs Jane). Tarzan's velocity at the bottom of the downswing will be the only unknown.

Step 2: Use conservation of momentum to equate Tarzan's momentum before he grabs Jane to the momentum of the Tarzan-Jane system right after he grabs her. You have already found Tarzan's velocity right before he grabs Jane, so their new, joint velocity will be your only unknown.

Step 3: Use conservation of energy again, this time to equate the kinetic energy of Tarzan and Jane at the bottom of the upswing (which uses the velocity you just found) to their gravitational potential energy at the top of the upswing. This time, the height of the upswing will be your only unknown, and is your final answer.

2007-11-02 08:02:35 · answer #1 · answered by DavidK93 7 · 0 0

ok sounds what im doing right now... 9th grade conceptual physics...

Mass (m)= 85+60=145 because you have to add jane to tarzan
distance(d)=3.5m
acceleartion (a)= 10m/s squared (as always)

uh-oh... hold on... we havent learned an equation for this yet... sorry....

but we wre studing elastid and inelastic collisions and how to find distance given the mass and stuff

idk sorry

2007-10-30 13:20:51 · answer #2 · answered by Anonymous · 0 1

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