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a baseball has mass .145. If the velocity of a pitched ball has a magnitude of 40.0 m/s and the batted ball's velocity is 65.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball.

2007-10-30 12:22:08 · 2 answers · asked by h k 2 in Science & Mathematics Physics

2 answers

Momentum, p, is found using the equation p = mv, where m is mass and v is velocity. The ball's original momentum is (0.145 kg)(40.0 m/s) = 5.8 kg-m/s. The ball's final momentum is (0.145 kg)(-65.0 m/s) = -9.425 kg-m/s. The change is therefore (5.8 kg-m/s) - (-9.425 kg-m/s) = 15.2 kg-m/s.

2007-11-02 05:47:15 · answer #1 · answered by DavidK93 7 · 0 0

scientific notation 1.52x10^-1 or 15.225m/s

get a second opinion though

2007-10-30 19:31:43 · answer #2 · answered by MeDIGURU 1 · 0 0

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