Your numbers don't add up... and you haven't specified the dimensions of the tiles (are they 1 sq. ft.?)
Generally, when you have an L-shaped room, break it into two rectangles. Figure the area of the two rectangles using:
A = L x W
Add the two together and that is your total square footage.
Finally multiply this by your tile price (assuming they are 1 sq. ft.) to get the total cost.
For example, let's assume the dimensions were 76' along the bottom, 40' on the left, 38' at the top, *20'* down, over another 38' and then down 20'.
Then you have two rectangles:
40' by 38' and 20' by 38'
The areas are:
40 x 38 = 1,520 sq. ft.
20 x 38 = 760 sq. ft
Total is 2,280 sq. ft.
Multiply this by $1.19 per sq. foot
2,280 x 1.19 = $2,713.20
Or if your dimensions were: 76' along the bottom, 40' on the left, 38' at the top, 12' down, over another 38' and then down *28'*, then you have the following two rectangles:
40' by 38' and 28' by 38'
The areas are:
40 x 38 = 1,520 sq. ft.
28 x 38 = 1,064 sq. ft
Total is 2,584 sq. ft.
Multiply this by $1.19 per sq. foot
25,84 x 1.19 = $3,074.96
2007-10-30 12:01:39
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answer #1
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answered by Puzzling 7
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Your dimensions so not add up. If the left side is 40 feet, then 12 + right side must = 40 so right side = 28, not 12.Assuming you meant 28 feet, the answer is 38*40 +38*28 = 2548 ft^2.
If you meant to go down 20 feet instead of 12 feet, the answer is 38*40+38*20 = 38*60 = 2280 ft^2
Assuming the tiles are 1 foot squares, you will need either
2548 or 2280 tiles. Cost will be $3,032.12 or$2713.20
with the assumption that the units of 1.19 is dollars.
2007-10-30 12:09:29
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answer #2
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answered by ironduke8159 7
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