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Find turning point, rel. minimum or max., and point of inflection for:

f(x)=x^2-4/x

and

g(x)=1/3x^3-x^2+x-3

Thanks in advance!

2007-10-30 08:37:38 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

f´(x) = 2x+4/x^2 = (8x^3+4)/x^2 = 0 so x= (-1/2)^1/3 local minimum
f´´(x) = 2-8/x^3 = 0 //2x^3-8=0 // x=(4)^1/3 inflection point
g´(x) = x^2-2x+1 =0 //x=1 (double root) no max nor min)
g´´(x) 2x-2=0 //x=1 //inflection point

2007-10-30 09:02:30 · answer #1 · answered by santmann2002 7 · 0 0

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