Can you do this math problem of the week?

Question

BXDE=ABC
A,B, and C are consecutive digits. D and E are also consecutive digits. A, B, C, D, and E are all different digits. If B x DE = ABC, find the sum of A+B+C+D+E. (Note: C and D are not necessarily consecutive digits.)

Answer 1

DE
x B
------
ABC

ABC = {123, 234, 345, 456, 567, 678, 789}
DE = {12, 23, 34, 45, 56, 67, 78, 89}
B = {2, 3, 4, 5, 6, 7, 8}

A little trial and error and you find B = 3, DE = 78 results in 234.

For completeness, here is the full list of results for B * DE:

2 * DE = {24, 46, 68, 90, 112, 134, 156, 178}
3 * DE = {36, 69, 102, 135, 168, 201, *234*, 267}
4 * DE = {48, 92, 136, 180, 224, 268, 312, 356}
5 * DE = {60, 115, 170, 225, 280, 335, 390, 445}
6 * DE = {72, 138, 204, 270, 336, 402, 468, 534}
7 * DE = {84, 161, 238, 315, 392, 469, 546, 623}
8 * DE = {96, 184, 272, 360, 448, 536, 624, 712}

Only one of these results in consecutive digits:
ABC = 234
DE = 78
A + B + C + D + E = 24

Answer 2

3 x 78 = 234
2+3+4+7+8 = 24

Answer 3

Actually that question is not worded right, zero is not a digit, it's a value.