Pre-Calculus question?

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Pre-Calculus question?

Hi I really need your help!

Which of the following is not a function given that x is an independent variable?

a. y= 6sqrtx, x>=0
b. {(6,4), (-2,1), (10, -1)}
c. y=6x^2-4
d. x=6y^2-4

Please help!

2007-10-30 07:26:04 · 2 answers · asked by Veronica K 3 in Science & Mathematics ➔ Mathematics

2 answers

This one was up yesterday. Functions can have only one y value for any given x value in the domain.
Given any real x, y can have the value of sqrt[(x+4)/6] or
-sqrt[(x+4)/6] if x = 6y^2 - 4. "d" is still a relation, not a function.

2007-10-30 07:32:32 · answer #1 · answered by Hiker 4 · 0⤊ 0⤋

b. Three points do not a function make.

2007-10-30 14:30:11 · answer #2 · answered by gebobs 6 · 0⤊ 0⤋