A patient weighs 146 pounds and is t orecieve a drug at a dosage of 45.0 mg per kg of body weight. The drug is supplied as a solution that contains 25.0 mg of drug per mL. How many mL of the drug should the patient recieve?
(1 pound= 454grams)
2007-10-30 07:25:37 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
(146 lb) (454 g/lb) (kg/1000g) = 66.3 kg subject weight
mg of serum needed = 66.3 kg * 45 mg/kg = 2983 mg serum
concentration serum = 25 mg/ml
2983 mg = x mg * 25 mg/ml ==> x ml = 119 ml serum
2007-10-30 07:35:50 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
Wow! A lot of conversions here!
If the person is to receive 45 mg per kg, let's first find out how much the patient needs of the medicine. If the guy weighs 146 pounds, that means that he weighs 146*454=66284 grams, or (because 1000g=1kg) 66.284 kg. (Makes sense?)
If he needs 45mg per kg, that means that he will need 45*66.284=2982.78mg of medication. Ok...so now we're on a roll.
We know how much medication he needs, but since it is in a solution, we need to find out how much solution he will need. Since one mL of solution contains 25 mg of what we need, we will need we need to divide what we need by 25 to get the mL. 2982.78/25=119.3112mL.
2007-10-30 07:42:49 · answer #2 · answered by evanbartlett 4 · 0⤊ 0⤋
Let the drug be called D; let the drug solution be called DS.
146lb x 454g/1lb x 1kg/1000g x 45.0mgD/1kg x 1mLDS/25.0mgD = 119 mL DS
2007-10-30 07:34:18 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋
17.365
2007-10-30 07:28:37 · answer #4 · answered by Anonymous · 0⤊ 0⤋