E,n=0, 3^n/((5^n)*n!)
2007-10-30 07:11:31 · 4 answers · asked by sugardaddy8815 1 in Science & Mathematics ➔ Mathematics
This is just the series expansion for e^x, where we let x = 3/5, so the answer is e^(3/5), or about 1.82212.
2007-10-30 07:28:08 · answer #1 · answered by Scythian1950 7 · 0⤊ 1⤋
where is the upper bound? so brute forcing
n=0 to 0, sum =1
n=0 to 1, sum =8/5
n=0 to 2, sum =89/50
n=0 to 3, sum =227/125
n=0 to 4, sum =9107/5000
n=0 to 5, sum =56939/31250
n=0 to 6, sum =2277641/1250000
n=0 to 7, sum =39858839/21875000
n=0 to 8, sum =3188707849/1750000000
n=0 to 9, sum =498235609/273437500
n=0 to 10, sum =497176975129/437500000000
fastidious, just give me the upper bound!
2007-10-30 14:20:04 · answer #2 · answered by ¥€$ 3 · 0⤊ 1⤋
a_n=( 0.6)^n/n! which is the term of the series for e^0.6=1.8221
2007-10-30 14:23:59 · answer #3 · answered by santmann2002 7 · 0⤊ 1⤋
yikes!
2007-10-30 14:18:46 · answer #4 · answered by Axis Flip 3 · 0⤊ 0⤋