howto do this help!!!!!
2007-10-30 06:45:09 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(3x+4)(x^2-8x+2)
=3x^3-24x^2+6x+4x^2-32x+8
=3x^3-20x^2-26x+8
2007-10-30 06:50:12 · answer #1 · answered by Grampedo 7 · 0⤊ 1⤋
multiply
(3x + 4)(x^2 - 8x +2) distrubt
3x (x^2 - 8x +2) + 4(x^2 - 8x +2)
3x^3 - 24x^2 + 6x +4x^2 - 32x + 8 combine like terms
3x^3 - 20x^2 - 26x + 8 would be how you would simplify
2007-10-30 06:50:29 · answer #2 · answered by Arin 3 · 0⤊ 0⤋
What is the value of this equation? Is it zero, i.e.,
(3x+4)(x^2-8x+2) = 0 ?
If the product is zero, then at least one of the factors equals 0, i.e.,
(3x+4)=0
(x^2-8x+2)=0
You can solve the first one by rearranging terms. Use the quadratic equation to solve the second.
2007-10-30 06:51:32 · answer #3 · answered by DWRead 7 · 0⤊ 0⤋
Do 3x(x^2-8x+2) and then 4(x^2-8x+2)
2007-10-30 06:53:30 · answer #4 · answered by Jen 3 · 0⤊ 0⤋
multiply each term through:
(3x+4)(x^2-8x+2)=
3x*x^2-3x*8x+3x*2+4*x^2-4*8x+4*2=
3x^3-24x+6x+4x^2-32x+8=
2x^3-50x+8
2007-10-30 06:52:57 · answer #5 · answered by Scott 3 · 0⤊ 0⤋
3x^3-24x^2-32x+4x^2+8+6x
3x^3-20x^26x+8
2007-10-30 07:05:07 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
------x^2 - 8x + 2
------------ 3x + 4
3x^3 - 24x^2 + 6x
-----------4x^2 -32x + 8
------------------------------
3x^3 - 20x^2 -26x + 8
2007-10-30 06:51:16 · answer #7 · answered by norman 7 · 0⤊ 0⤋