What is [HONH3+] for a 0.350 M solution of Hydroxylamine HONH2 Kb = 1.10e-8?

Answer 1

HONH2 + H2O <===> HONH3+ + OH-

Kb = [HONH3+][OH-] / [HONH2] = 1.1 x 10^-8

[H2O] = 1 by convention. [HONH3+] = [OH-] = x. [HONH2] = 0.350 - x, which is essentially 0.350, because x is so small.

x^2 / 0.350 = 1.1x10^-8

x^2 = 3.8 x 10^-7 = 38 x10^-8

[HONH3+] = x = 6.20 x 10^-4M