English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

An alpha particle (mass = 6.6 10-24 g) emitted by radium travels at 2.5 107 0.1 107 mi/h.
(a) What is its de Broglie wavelength (in meters)?

(b) What is the uncertainty in its position?

2007-10-30 05:48:37 · 1 answers · asked by jnester0289 1 in Science & Mathematics Chemistry

1 answers

The de Broglie equation relates the wavelength λ to the particle velocity ν is:
λ = (h/m)sqrt(1/ν^2 - 1/c^2)
where λ is the de Broglie wavelength (in meters), h the Plank constant 6.626x10^-34 J·s, m the mass of the particle in kg, ν the velocity of the particle in m/s, and c the speed of light 2.998x10^8 m/s. Once m and ν are given, λ can be calculated.
Unfortunately I do not understand what you mean about "travels at 2.5 107 0.1 107 mi/h". Please check the problem and solve it yourself.

(b) I am not very sure.

2007-10-31 12:22:26 · answer #1 · answered by Hahaha 7 · 0 0

fedest.com, questions and answers