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2007-10-30 02:35:10 · 4 answers · asked by janelle 1 in Science & Mathematics Mathematics

4 answers

MMMMDLXDCXXX, where there is a separate line over each of the MMMMDLX. Or a heck of a lot of M's followed by DCXXX to do it the classical way.

2007-10-30 02:48:02 · answer #1 · answered by xwdguy 6 · 0 0

Hello

I just taught this lesson to my class the other day.

Here is our basic list of Roman Numerals:

I 1 (one) (unus)
V 5 (five) (quinque)
X 10 (ten) (decem)
L 50 (fifty) (quinquaginta)
C 100 (one hundred) (centum)
D 500 (five hundred) (quingenti)
M 1000 (one thousand) (mille)

For large numbers (4000 and above), a bar is placed above a base numeral to indicate multiplication by 1000:

V (bar) for five thousand
X (bar) for ten thousand
L (bar) for fifty thousand
C (bar) for one hundred thousand
D (bar) for five hundred thousand
M (bar) for one million

Just picture a bar above these previous letters.

For very large numbers, there is no standard format, although sometimes a double bar or underline is used to indicate multiplication by 1,000,000. That means an underlined X (X) is ten million

So 4,560,630 would be

(IV) Double bar) (D Bar) (LI (Bar)) DC XXX

Hope this helps

2007-10-30 09:50:25 · answer #2 · answered by Jeff U 4 · 0 0

Most people know the basic letters, but here they are:

I = 1
V = 5
X = 10
L = 50
C = 100
D = 500
M = 1,000

Beyond that, you put a line over the letter to multiply by 1000. Since I can't do that here, I'll put an apostrophe:

I' = 1,000
V' = 5,000
X' = 10,000
L' = 50,000
C' = 100,000
D' = 500,000
M' = 1,000,000

Beyond that, you put two lines over the letter, or one line over and one line below. Again I'll use apostrophes:

I'' = 1,000,000
V'' = 5,000,000
X'' = 10,000,000
L'' = 50,000,000
C'' = 100,000,000
D'' = 500,000,000
M'' = 1,000,000,000

So, to write 4,560,630 would be I''V''D'L'X'DCXXX

2007-10-30 09:52:18 · answer #3 · answered by Neebler 5 · 0 0

M(line above)V(underlined) = 4,000,000
DLX(line above) = 560,000
CDXXX = 630

2007-10-30 09:52:31 · answer #4 · answered by dpobyc 2 · 0 0

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