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2007-10-30 01:02:38 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

2x + y = 5
5x +3y = 11

Take the first equation are rearrange it:

y = 5 - 2x

Now replace y in the second equation by (5 - 2x):

5x + 3(5 -2x) = 11

and simplify

5x + 15 - 6x = 11
4 - x = 0

So x = 4

y = 5 - 2x, so y = -3

final check

2x + y = 5 yup
5x + 3y = 11 yup

2007-10-30 01:14:00 · answer #1 · answered by Computer Guy 7 · 0 0

when you say addition, do you mean elimination? cause elimination can be done by addition or subtraction.

addition:

get rid of one variable say x by multiplying both coefficients of x with a certain number to eliminate it.

-5(2x + y = 5)
2 (5x + 3y = 11)
distribute -5 to 2x + y = 5 and distribute 2 to 5x + 3y = 11.

we get:
-10x -5y = -25
10x + 6y = 22 then add the two equations:

-10x - 5y = -25
+ 10x + 6y = 22
= 0x + y = -3 notice that we do not have a value for x anymore so we get:

y= -3 -----> this is the value of y.

solving for x:

-3(2x + y = 5)
5x + 3y = 11 we get:

-6x - 3y = -15
+ 5x + 3y = 11
= -x + 0y = -4 no value for y anymore so,

-x = - 4 therefore; x = 4.

2007-10-30 08:34:19 · answer #2 · answered by gvlumbao 2 · 0 0

OKay,im assuming the equations are 2x+y=5 and 5x+3y=11.
So, multiply 1st equation by -3, giving us -6x-3y=-15.
-x=-4, so x=4.
And (2*4)+y=5, so y=5-8=-3.
So, x=4, y=-3.

2007-10-30 08:23:57 · answer #3 · answered by yljacktt 5 · 0 0

2x + y =5
2(2) + 1 = 5


5x + 3y=11
5 (1) + 3(2) =11

solve by adding

2 + 2+ 1= 5
5 + 2+2+2 = 11

2007-10-30 08:14:32 · answer #4 · answered by theresa b 2 · 0 0

first write the question properly & legibly we can't say if it's
2x+y=55, x+3y=11 or
2x+y=5, 5x+3y=11
first clearly wrie this.

2007-10-30 08:15:21 · answer #5 · answered by venky 2 · 0 0

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