angular acceleration?

Question

If a CD rotates at 500 rpm while the last song is playing, and then spins down to zero angular speed in 2.60 s with constant angular acceleration, what is the magnitude of the angular acceleration of the CD, as it spins to a stop?

how many complete revolutions does it make as it spins to a stop?

Answer 1

Acceleration is the change in velocity over time
Therefore:
A= (0 rpm- 500 rpm)/2.6 sec
=-192 rpm/sec
=-3.2 revolutions/sec^2

convert to deg/sec^2
=-3.2 rev/sec^2* 360deg/rev=-1153 deg/sec^2

convert to rads/sec^2

=-3.2 rev/sec^2*2pi rads/rev= -20.1 rads/sec^2