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To estimate the height of a building, a stone is dropped from the top of the building into a pool of water at ground level. How high is the building if the splash is seen 5.6 seconds after the stone is dropped?

2007-10-29 14:51:56 · 1 answers · asked by JerseyGirl 2 in Science & Mathematics Engineering

1 answers

You are told

S(t) = at^2 + bt + c

When the stone is dropped, its initial velocity, V0 is 0, so b = 0.
We can choose the origin of the system to be at the top of the building so S(0) = 0.

So S(t) will be the distance from the top of the building at time t.

At t = 5.6, the position is ground level.

So what's the problem?

2007-11-01 20:14:19 · answer #1 · answered by simplicitus 7 · 0 1

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