Need a new haircut?

Question

I am a male, I have dark brown hair, its moderately thick, and I cannot be bothered with trying to make my hair look perfect, I am not that great at fixing up my hair in the morning. I am a freshman college student. I want a haircut that is relatively short, since my hair grows fast (I don't mind going for frequent haircuts to keep the look).

I am basically trying to find an easily manageable haircut, that gives off the idea of clean & sharp, business like, and is easy to do with some gel/paste or the like in the morning. (If you have a gel/paste brand&type recommendation all the better). I would also like to be able to give it a messy look when possible. I think the spikey look makes me look kind of young. I am not built anywhere except moderately in chest, and alot in legs, but I am going to be building up my arms a good bit now.

suggestions?I type in this stuff in google and it gives me crazy model hairstyles that no guys actually do.
Would pref. pictures with suggestions

Answer 1

I like the short and messy like Brad Pitt

try these sites or Google B. Pitt:

bosshairstyles.com
matrix.com
hrhairstyles.com

Answer 2

A fairly professional hairstyle that is easy would be this one,

http://www.thehairstyler.com/celebrity_hairstyle.asp?name=David+Beckham

the 2nd and 3rd from the bottom. They are easy to maintain and they look professional.

Another decent one would be,

http://www.thehairstyler.com/celebrity_hairstyle.asp?name=Josh+Duhamel

or

http://www.thehairstyler.com/celebrity_hairstyle.asp?name=Jake+Gyllenhaal

either of those. Yes i know there all celeberities, but these styles are in and easy to keep looking good etc. For products use American Crew Forming Cream for the first ones, and the second you could probably go with American Crew Pomade. Hope this helps.

Answer 3

Try a high fade. My husband is military. He's got thick, fast growing hair as well. I'm not saying you have to go as high, or as thin, but it's something you should look into. I attached a link to pictures.