Word Problem. Check Answer?

Question

Ten cars containing a total of 32 people passed through a checkpoint. If none of these cars contained more than 4 people, what is the greatest possible number of these cars that could have contained exactly 2 people?
A - 1
B - 2
C - 3
D - 4
E - 5

I picked E) 5. I'm doubtful of its correctness, so can anyone clarify or give me pointers how to arrive at the correct answer if I'm wrong?

Where did you get 10-x, please, second respondent? I understand the logic of everything but where did 10-x derive from?

Answer 1

if x= number of cars with 2 people
2x+4(10-x)=32
2x+40-4x=32
2x=8
x=4

If there are 4 cars with 2 people that is 8 people leaving 24 for the other six cars. That would be 4 each in all of them. No more can be had. Choice D.

Answer 2

The answer is D - 4

If 5 cars carry 2, that's 10 people and subtract that from 32, you need to carry 22 more people in the following 5 cars. 5 cars x 4 (the max in a car) is only 20 so you would be short 2.

4 x 2 = 8
32-8 = 24
24 people in 6 cars = 4 each car, which is also you max in a car so that works.

For these questions, you can quickly try work on a couple of answers until you see which may be right or not.

Answer 3

in simple terms write s/a million = m/3 = l/5 there's a property that enables us to characteristic the numerators and denominator... so we get: s/a million = m/3 = l/5 = (s+m+l)/(a million+3+5) or s/a million = m/3 = l/5 = 126/9 = 14 Now s/a million = 14 ==> s= 40 2 m/3 = 14 ==> m= 40 2 l/5 = 14 ==> l = 70

Answer 4

The answer would be D.
Because when you put 2 people in 4 cars that would be 8 people and you would be left with 24 people and 6 cars. You put 4 people in each car and you're clear.

Answer 5

2x+40-4x=32
8=2x
x=4