Help math word problem urgent!?
Andy,Bob,Chris split $1,000 among them to be invested in diff. ways. each begins with a different amount of money!!!!! . at the end of the year they have a total of $1,500. bob and chris have both doubled their money, while andy has lost $100. what was andy's original portion?
2007-10-27 14:11:44 · 5 answers · asked by ~USA~ 2 in Science & Mathematics ➔ Mathematics
Andy's portion: a
Bob's portion: b
Chris' portion: c
a + b + c = 1000
After one year:
Andy's portion: (a-100)
Bob's portion: 2b
Chris' portion: 2c
a - 100 + 2b + 2c = 1500
a + 2b + 2c = 1600
a + b + c = 1000
-------------------------
b + c = 600
a = 1000 - (b + c) = 400
Andy's original portion was $400
2007-10-27 14:21:22 · answer #1 · answered by gudspeling 7 · 1⤊ 0⤋
Bob and Chris had $250 and $350, Andy had $400.
Bob and Chris doubled their money to make a total of (250 + 350) x2 = 1200, and Andy lost $100, making 300 + 1200 = $1500.
2007-10-27 14:20:25 · answer #2 · answered by attakkdog 5 · 0⤊ 1⤋
400
Bob and Chris made 600 profit combined since their 600 profit minus 100 loss by andy equaled 1500. Now if they doubled their money they had to start with a combined total of 600 also. That leaves Andy with 400 as 1200 + 400 - 100 loss = 1500.
2007-10-27 14:21:23 · answer #3 · answered by A fan 4 · 0⤊ 1⤋
A + B + C = 1000
2B + 2C + A - 100 = 1500
2(B + C) + A - 100 = 1500
2(B + C) = 1600 - A
B + C = 800 - 0.5 A
A + (800 - 0.5 A) = 1000
0.5 A = 200
A = $400
The amounts for the other two aren't necessary, so this is what would make most sense to me.
2007-10-27 14:21:59 · answer #4 · answered by lhvinny 7 · 1⤊ 0⤋
x=Bob
y=Chris
z=Andy
x+y+z=1000
2x+2y+z-100=1500
x+y=600
z=400 was Andy's portion
Bob and Chris have to add to 600 but there isn't enough information to know exactly what they had.
2007-10-27 14:28:58 · answer #5 · answered by chasrmck 6 · 2⤊ 0⤋