2007-10-27 14:09:34 · 3 answers · asked by soccer_maniaco 1 in Science & Mathematics ➔ Chemistry
All nitrates are readily soluble in water, but a number of sulfates, such as barium or lead, are not. Adding some of the sample to a solution of a nitrate of such a metal should result in a precipitate if sulfate ion is present.
2007-10-27 14:15:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
First acidify a sample of solution with HNO3.
Then, add in barium nitrate (BaNO3)
A white precipitate would be observed if SO4 2- is present.
*All nitrate salts are soluble in water.
Ba2+ (aq) + SO4 2- (aq) ---> BaSO4(s)
2007-10-27 23:40:09 · answer #2 · answered by Tinky 2 · 0⤊ 0⤋
Add BaCl2 solution. Add a bit of HNO3 to make sure nothing else interferes.
BaCl2(aq) + SO4= ===> BaSO4(s) + 2Cl-
2007-10-27 21:13:50 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋