a.Ba(NO3)2 + NH2SO3H + H2O → Ba(NH2SO3)2 + HNO3
b. Ba(NO3)2 + NH2SO3H + H2O → BaSO4 + NH4NO3 + HNO3
c. Ba(NO3)2 + NH2SO3H + H2O → Ba(NH2)2 + H2SO4 + HNO3
2007-10-27 14:03:30 · 4 answers · asked by sam h 1 in Science & Mathematics ➔ Chemistry
thank you for not helping at all... I have tried them on my own
2007-10-27 14:09:23 · update #1
im not asking to be spoon fed anything... i have tried these problems on my own. i asked this question for help so if yuou dont want to help stop answering the question!
2007-10-27 14:35:39 · update #2
a.Ba(NO3)2 + 2NH2SO3H → Ba(NH2SO3)2 + 2HNO3 (I assume the H2O is just the solvent here?)
b. Ba(NO3)2 + NH2SO3H + H2O → BaSO4 + NH4NO3 + HNO3 (this one appears balanced)
c. Ba(NO3)2 + 2NH2SO3H + 2H2O → Ba(NH2)2 + 2H2SO4 + 2HNO3
2007-10-27 14:40:33 · answer #1 · answered by ChemistryMom 5 · 0⤊ 0⤋
Just write down a running total of the number of elements on both sides of each equation, start multiplying each element by a factor to equate it on the other side (making sure to apply the same to the other side), and continue this until you are done. After this, look at your stoichiometric coefficients and compare them. If they share a common multiplicative factor, divide all coefficients by this number.
2007-10-27 21:21:58 · answer #2 · answered by Ray S 2 · 1⤊ 0⤋
Please provide additional details on the (molecular) or atomic mass of each elements for speedy answer.
Don't expect to have spoon feeding answers. You have to do your part too.
Or are you just testing us members to solve this prob?
With your response, I may provide solution in an edited manner.
2007-10-27 21:28:53 · answer #3 · answered by rene c 4 · 0⤊ 1⤋
you really should do these on your own. Just do it step by step; make sure there's an equal number of atoms on each side.
2007-10-27 21:08:23 · answer #4 · answered by Yi 2 · 1⤊ 0⤋