((x^2 - x)/(x)) * ((2x+3)/(x - 1))?

Question

Given that f(x)= (x^2 – x)/x and g(x)= (2x+3)/(x – 1), find f(x) * g(x).

I need to write a test for my Pre-Calc midterm and just wanted to make sure this was correct.

the answer I got was 2x+3. is it right? show your work please ;]

Answer 1

((x^2 - x)/(x)) * ((2x+3)/(x - 1))?
x(x-1)/(x) * ((2x+3)/(x - 1))
yup the x-1 cancel top and bottom and the x s cancel also
yr right

Answer 2

f(x) = x - 1
g(x) = (2x+3)/(x-1)

(x-1)/(x-1) = 1

(2x + 3) * 1 = (2x+3)

Your answer is correct. Just have to keep in mind that the domain of f(x) * g(x) would not include the integers 0 or 1.

Answer 3

[(x^2 - x) / x] (2x + 3) / (x - 1)

= [x(x - 1) / x] (2x + 3) / (x - 1)

= (x - 1) (2x + 3) / (x - 1)

= 2x + 3