Solve the Quadratic Equation using the Square Root Principle, Completing the Square, or the Quadratic Formula
(x – 5)^2 = 16
thankyou
2007-10-27 13:26:27 · 13 answers · asked by sumguy 1 in Science & Mathematics ➔ Mathematics
Use FOIL - First Outside Inside Last
(x-5)(x-5)=16
FIRST: x^2
OUTER: -5x
INSIDE: -5x
LAST: -5*-5 = 25
Add em up
x^2 -10x+25=16
Reduce
x^2-10x+9=0
Another way of writing this is
(x-9)(x-1)=0
x=9 or x=1
2007-10-27 13:35:34 · answer #1 · answered by WonderingMan 2 · 0⤊ 0⤋
9
Take the square root of BOTH the left and right side. That cancels out the ^2 and makes the 16 a 4.
Add 5 to both sides. That Leaves x on its own and makes the 4 a 9.
2007-10-27 20:28:30 · answer #2 · answered by Grouchy Boulder 2 · 0⤊ 1⤋
x=9
2007-10-27 20:36:42 · answer #3 · answered by ... 4 · 0⤊ 0⤋
x-5 = 4 , x =9
2007-10-27 20:29:55 · answer #4 · answered by Suzanne 1 · 0⤊ 1⤋
the answer is 9 because 9-5=4 and 4 squared is 16
2007-10-27 20:29:35 · answer #5 · answered by divapink12 2 · 0⤊ 1⤋
(x-5)^2 = 16
(x-5)(x-5) = 16
x^2 -10x +25 = 16
x^2-10x +9 = 0
errr this is where my brain has given up on me...
a=1 b=-10 c=9
possibly use x=-b +or - the square root of (b^2 - 4ac) ...all of that<< divided by 2a
2007-10-27 20:33:23 · answer #6 · answered by <,"(((>< 3 · 0⤊ 1⤋
(x – 5)^2 = 16
x^2 - 10x + 25 = 16
x^2 - 10x + 9 = 0
(x - 9)(x - 1) = 0
x - 9 = 0 and x - 1 = 0
x = 9 and x = 1
2007-10-27 20:30:58 · answer #7 · answered by 1294 4 · 1⤊ 0⤋
square root of 16 is 4.
plus 5=
Nine.
The key is to get 'x' by itself.
2007-10-27 20:35:07 · answer #8 · answered by Caroselambra 2 · 0⤊ 0⤋
(x – 5)^2 = 16
x-5 = +/-4
x = 9, or x = 1
2007-10-27 20:30:53 · answer #9 · answered by Robert S 7 · 1⤊ 0⤋
so multiply it out
then subtract 16 from both sides (it's an equation)
then solve
x^2 -25x +25 = 16
x^2 -25x +9 = 0
and you're stuck at that point
2007-10-27 20:30:42 · answer #10 · answered by tom4bucs 7 · 0⤊ 1⤋