simplify (z+3)(3z^2 + z-1)?

1 ⤊

2007-10-27 13:14:17 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

[5]
(z+3)(3z^2+z-1)
=z(3z^2+z-1)+3(3z^2+z-1)
=3z^3+z^2-z+9z^2+3z-3
=3z^3+10z^2+2z-3

2007-10-27 13:19:54 · answer #1 · answered by alpha 7 · 0⤊ 0⤋

I'll assume you want to get the product
= 3z^3 + z^2 - z + 9Z^2 + 3z - 3
= 3z^3 + 10z^2 + 2z - 3

2007-10-27 13:21:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋

(z+3)(3z^2 + z-1)
= 3z^3 + 10z^2 + 2z - 3

2007-10-27 13:18:07 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋

3zÂ³ + zÂ² - z
___9zÂ² + 3z - 3

3zÂ³ + 10zÂ² + 2z - 3

2007-10-31 08:06:50 · answer #4 · answered by Como 7 · 0⤊ 1⤋

Simplify it yourself, this is answers, not domyhomeworkforme.com!

2007-10-27 13:20:05 · answer #5 · answered by Anonymous · 1⤊ 1⤋