-1 as a zero of multiplicity 3
0 as a zero of multiplicity 2
and
1 as a zero of multiplicity 1
f(x)=?
Use 1 for the leading coefficient
2007-10-27 12:28:19 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
[(x+1)^3] [x^2] [(x-1)], then rewrite it:
f(x) = x^2(x-1)(x+1)^3
You can multiply it out if you need to.
2007-10-27 12:35:24 · answer #1 · answered by Marley K 7 · 1⤊ 0⤋
x^6-x^3+1
2007-10-27 12:33:01 · answer #2 · answered by Vida Joy 3 · 0⤊ 0⤋
root: -1
(x - (-1))^3
(x + 1)^3 is one of the factor
root: 0
(x - 0)^2
root: 1
(x - 1)
f(x) = (x + 1)^3 * x^2 * (x - 1)
now just distribute and you'll get:
f(x) = x^6 + 2x^5 - 2x^3 - x^2 <== answer
2007-10-27 12:37:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋
p(x)=x^2 * (x+1)^3 * (x-1)
=x^2 * (x^3 + 3x^2 + 3x + 1)(x-1)
= x^2 * (x^4 - 2x^3 - 2x - 1)
= x^6 - 2x^5 - 2x^3 -x^2
2007-10-27 12:35:01 · answer #4 · answered by norman 7 · 0⤊ 0⤋
f(x)=x^2(x-1)(x+1)^3
f(x)=x^2(x^2-1)(x^2+2x+1)
f(x)=x^2(x^4+2x^3-2x-1)
f(x)=x^6+2x^5-2x^3-x^2
2007-10-27 12:35:01 · answer #5 · answered by Greg D 2 · 0⤊ 0⤋