a cat running a horizontal surface jumps off a roof 5.8 meters away. he grabs a building 3.7 meters below his starting point. what is his initial velocity?
2007-10-27 11:53:18 · 2 answers · asked by magna1211@sbcglobal.net 1 in Science & Mathematics ➔ Physics
please explain and if possible show how to do it.
2007-10-27 11:55:49 · update #1
6 to 8 m/s.
2007-10-27 11:55:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
First you find his time of flight t from g and height h (= 3.7 m).
h = gt^2/2 ==> t = sqrt(2h/g)
From the wording of the question, the cat's velocity is all horizontal.
V = hor. velocity Vx = 5.8/t m/s.
That's the concept; you can produce the answer.
Hint: It's not anywhere near 11.4, more like 6 to 8 m/s.
EDIT: ...6 to 8 m/s (as the 1st answerer changed his answer to agree with)
2007-10-27 14:37:01 · answer #2 · answered by kirchwey 7 · 0⤊ 1⤋