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Consider the 74 N weight held by two cables shown. The left hand cable is horizontal.

http://img120.imageshack.us/img120/3038/111if3.jpg

What is the tension in the cable slanted at an angle of 53 degrees. Answer in N

What is the tension in the horizontal cable? Answer in N

2007-10-27 11:40:09 · 2 answers · asked by XzoeyX 2 in Science & Mathematics Mathematics

2 answers

Hi,
Let T1 be the tension of the line at 53 degrees and T2 be the other line connected to the side wall.
ΣFx = T1 Cos 53 – T2 Cos 0 = 0 …. (Eq 1)
ΣFy = T1 Sin 53 +T2 Sin 0 -74=0…. (Eq2)
T1 Sin 53 +0 = 74…. (From Eq 2)
.6018T1 =74
T1 = 122.96
T1Cos53 =T2 Cos 0 (from Eq 1)
T1 Cos 53 = T2
122.96 (.6018) = T2
T2 = 74

FE

2007-10-27 16:04:28 · answer #1 · answered by formeng 6 · 0 0

234

2007-10-27 11:54:38 · answer #2 · answered by Anonymous · 0 0

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