2007-10-27 11:15:27 · 4 answers · asked by Ronny A 1 in Science & Mathematics ➔ Mathematics
For cos(x) the series is
1 - x^2/2! + x^4/4! - x^6/6! + ...
so for x^3 the series would be
1 - x^6/2! + x^12/4! - x^18/6! ....
2007-10-27 11:22:33 · answer #1 · answered by PeterT 5 · 0⤊ 0⤋
Maclaurin Series Cos
2016-12-16 04:17:36 · answer #2 · answered by trip 4 · 0⤊ 0⤋
A Maclaurin series is a special case of a Taylor series. The Maclaurin series is always about x = 0.
Σ fⁿ(0)xⁿ/n!
start with n = 0
f(0) = 1, n! = 1, x^0 = 1
So the first term is 1.
Repeat for increasing n to find the desired number of terms.
Find a pattern in the terms so you can write the whole series in sigma notation.
2007-10-27 11:29:13 · answer #3 · answered by Demiurge42 7 · 0⤊ 0⤋
The only thing you need to do for this problem is just substitution. I'll assume you know what the Maclaurin series for cos(x) is, then all you have to do is substitute x^3 everytime you see an x for the maclaurin series of cos(x).
2007-10-27 11:50:15 · answer #4 · answered by NBL 6 · 0⤊ 0⤋