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This question has bugged me for awhile. Find area inside the loop of the following limacon r= 5-10sin(theta). Please do not come up with 222.031538. I try and it's not correct. Anyone?

2007-10-27 10:37:30 · 1 answers · asked by V for V 2 in Science & Mathematics Mathematics

1 answers

I was wrong
To correct
Area inner loop = 1/8*100(2pi-3sqrt3)
Area between loops = 1/8*100 (4pi+3sqrt3)
Sum of: area between loops + area inner loop = 1/8*100*6pi=
235.6194
This in the case b=a/2 (this case)

2007-10-27 11:31:18 · answer #1 · answered by santmann2002 7 · 0 0

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