A racecar traveling at 44 m/s is uniformally accelarated to a velocity of 22 m/s over and 11 second interval. What is the displacement during this time?
Steps please.
2007-10-27 10:24:04 · 2 answers · asked by kickitup21 1 in Science & Mathematics ➔ Physics
v=@t+vo
22= @*11+44 so @=- 2m/s^2
d= 1/2@*t^2+vo*t
d=-121+44*11 =363m
2007-10-27 10:38:03 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
I would integrate here. You want to take the function that represents the speed, so creat that funtion first. (44-2*t) in this case. Then think about it and take that equation, and you can get the speed at any moment in time t. Now you need to get the displacement which is just time * speed = distance travelled. So Integral of (speed) from time 0 to time 11, will be the displacement during that time... written another way: Integral (lower limit = 0, upper limit = 11) 44-2*t
Which if you recal was that formal for current displacement we previously derived.
Hope that helps. :)
PS, message me and I can help you understand why this is the way you do it.
2007-10-27 17:34:21 · answer #2 · answered by Anonymous · 0⤊ 1⤋