What volume of Na2CrO4 solution is needed to precipitate all the Sr2+(aq) as SrCrO4?

Question

In the laboratory, 5.17 g of Sr(NO3)2 is dissolved in enough water to form 0.650 L. A 0.100 L sample is withdrawn from this stock solution and titrated with a 0.0360 M solution of Na2CrO4. What volume of Na2CrO4 solution is needed to precipitate all the Sr2+(aq) as SrCrO4?

(in liters)

Answer 1

The molar mass of Sr(NO3)2 is: 211.63g/mol.
(5.17g)*(0.100L/0.650L)/ (211.63g/mol) = 0.00376 mol

Volume of Na2CrO4 solution needed to precipitate all the Sr2+(aq) as SrCrO4 is:
(0.00376 mol)/ (0.0360 M) = 0.104L