MOLARITY help?

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If 54.8 mL of BaCl2 solution is needed to precipitate all the sulfate ion in a 544 mg sample of Na2SO4 (forming BaSO4), what is the molarity of the solution?

2007-10-27 07:43:29 · 1 answers · asked by JTOWN 2 in Science & Mathematics ➔ Chemistry

1 answers

Let BaCl2 solution be called BCS

BaCl2 + Na2SO4 ===> BaSO4 + 2NaCl

Atomic weights: Na=23 S=32 O=16 Na2SO4=142

544mgNa2SO4/54.8mLBCS x 1molNa2SO4/142gNa2SO4 x 1molBaCl2/1molNa2SO4 x 1000mLBCS/1LBCS = 0.0699 mole BaCl2 / 1L BCS, which is molarity to three sig figs.

2007-10-27 07:53:39 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋