"What is the probability of rolling 2 dice, and getting a total of 7 both times, on two consecutive rolls?"
Ok, I know you gotta make a quick diagram sorta thing (I don't know any other way to calculate the possible outcomes of a two-die roll, so I guess it will work alright...)
Then basically put X's where the totals equal 7, sorta like this...
1 2 3 4 5 6
1 X
2 X
3 X
4 X
5 X
6 X
So out of 36 outcomes, 6 appear to be desired (equal to 7).
So 1/6 equals the probability for 1 two-dice roll equalling 7.
So then just multiply it by itself for the probability for 2 two-dice roll equalling 7?
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Please verify this and also please answer if there is a more efficient way to determine how many desired outcomes there are, rather than graphing it out...
2007-10-23
10:47:10
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5 answers
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asked by
suezzle
3
in
Games & Recreation
➔ Gambling
Ah, crud... the format was auto-edited to delete the spaces in my graph. oh well, I think you know where they go.
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And hey...maybe I'm wrong...because the graph doesn't account for a 1 showing up on both dice as two seperate possible outcomes (1,1 or 1,1 / 2,2 or 2,2...etc......looks the same, but technically, wouldn't they be different possible outcomes, thus effecting probability? just as much as 2,3 and 3,2 are two seperate probabilities?)
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2007-10-23
10:50:47 ·
update #1