verizon said they wont support windows 95 any more does any one know how to create a loop hole. or any thing else.
2007-10-22 07:50:27 · 6 answers · asked by Anonymous in Computers & Internet ➔ Software
You need to get the drivers for your LAN card and then the Windows Networking pack which will allow you to put and IP address on that machine. Once those are in place, and properly configured, then you should be connected.
Microsoft does a good job of explaining it on thier site here:
http://support.microsoft.com/kb/132736
2007-10-22 07:58:39 · answer #1 · answered by Marvinator 7 · 0⤊ 0⤋
the provider is sturdy (maintains to be related) in my experience however the cost wasn't on the factor of that of my cable modem in long island with Cablevision. It rather relies upon on how briskly of a connection you have been experiencing with comcast. It varies from section to section. From what i've got seen in my section there is greater ability for speed in cable than dsl. My speed is around 30Mbps acquire & 5 Mbps upload. i've got by no potential seen DSL quicker than 2Mbps acquire and upload may well be dismall.
2017-01-04 07:09:44 · answer #2 · answered by ? 3 · 0⤊ 0⤋
Hi, if u can reconfigure ur router and ur user name and password in the routers configuration then what happens is that since the router is on all the time so u will always be connected and u won't need to dial in to ur service provider meaning ur connection will be on all the time. This works on speed touch routers, I am sure, but the others I don't have any idea. I hope I helped.
Good Luck!
2007-10-22 07:58:03 · answer #3 · answered by Anonymous · 0⤊ 1⤋
hello there was right, you should upgrade your operating system, at least upgrade to window 2000, depend on you
2007-10-23 02:56:17 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Windows 95, wow...... that is 12 years old. UPGRADE!!!!
2007-10-22 07:59:17 · answer #5 · answered by hello there... 3 · 1⤊ 1⤋
Dude, good luck with that; its really time to upgrade.
2007-10-22 07:56:24 · answer #6 · answered by isamuchan 2 · 0⤊ 1⤋