a sine wave has an instantaneous voltage of 60 volts after 90 deg. of rotation. what is the instantaneous voltage reached by this waveform after 110 deg. of rotation? this is for school, and my book does not really explane it very well...
2007-10-19 04:41:16 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
56.38v
2007-10-19 04:48:28 · answer #1 · answered by Anonymous · 1⤊ 0⤋
If this is a pure sine wave, you reach a complete cycle in 360 degrees.
At zero degrees, you have zero, at 90 degrees, you have the highest point (60 volts), at 180 degrees, you have zero again, at 270 degrees you have negative of the highest (-60 volts) and at 360 degrees, you have zero again.
So... you can say the voltage is expressed in the formula
e=Esin(angle)
where angle is measured in degrees
e is the instanteneous voltage
E is the highest possible voltage
Then what's your e at angle of 110 degrees? It'll be somewhere in the down-wards direction (but still positive) in the first half of the cycle.
2007-10-19 11:50:59 · answer #2 · answered by tkquestion 7 · 0⤊ 0⤋
Vmax * (sine(theta)=Vtheta
substitute 90 for theta to find the Vmax number, then use that number with 110 to find the answer....
2007-10-19 11:48:04 · answer #3 · answered by Steve E 4 · 0⤊ 0⤋
a-and-a gave the answer, but BRUZ shows you the formula.
It has been a long time since I did this stuff, it brings back some old memories.
2007-10-19 20:11:30 · answer #4 · answered by butch 5 · 1⤊ 0⤋
60sin(110)
2007-10-19 13:11:29 · answer #5 · answered by BRUZER 4 · 1⤊ 0⤋