HELP with circuit?

Question

I need to figure this out.
1. What is the percentage of error?
Measured versus calculated
Error formula = (calculated – measured/calculated x 100
For example (3.45 ohms - 3.127/3.45) x 100 = 9.36 %

I don't understand what thiis problem is asking. please help me out.

it might be about measured vs. calculated but im not too sure

Answer 1

It's exactly the way you wrote but for the parenthesis use...

You measure a length. Say: 7.5. The error is 0.1 because you are using a rule that measures cm and mm. Or, if you have a good eye, it could be 0.05cm. Ok, you can have other error's sources, but let's say that this is the only one.

So, you know that the real value will be between 7.6 and 7.4. This is what you mean when you write 7.5 +/- 0.1

But it's not the same to have 0.1 of error in 7.5, than to have 0.1 in 1 km. Do you get what I mean? So, althought the absolute error is the same, the relative one is a different thing

So, you have to calculate the percent of error

7.5 --- 100%
0.1 ---- x

And then x = 0.1*100/7.5

When you have a calculated value and a measured value, then you know what the absolute error is, in your example, 3.45 is the calculated value. But your measured value is 3.127

So, you find the difference and you do the same I did, and you get the percent.

Ilusion

Answer 2

You've completely failed to supply ANY relevant data for which the error is to be calculated.

Answer 3

???
What are you measuring? What is the actual measurement? What is the calculated value?

Doug